0=y^2-28y+196

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Solution for 0=y^2-28y+196 equation: 



0=y^2-28y+196

We move all terms to the left:

0-(y^2-28y+196)=0

We add all the numbers together, and all the variables

-(y^2-28y+196)=0

We get rid of parentheses

-y^2+28y-196=0

We add all the numbers together, and all the variables

-1y^2+28y-196=0

a = -1; b = 28; c = -196;
Δ = b2-4ac
Δ = 282-4·(-1)·(-196)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{-28}{-2}=+14$

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